| Previous page (Limits of functions) | Contents | Next page (Some horrible functions) |
-
definition of continuity.
Informally: Close points (
apart) are mapped to close points (
apart).
We formalise this to get the following:
Definition
R if
> 0 there exists
> 0 such that if |p - x| <
then |f(p) - f(x)| <
.
p. We must prove that (f(xn))
f(p).
> 0 we must find N such that |f(xn) - f(p)| <
if n > N.
from the new definition of continuity there is a
such that |f(xn) - f(p)| <
whenever |xn- p| <
.
Secondly, we show that the sequential definition implies the
-
one.
Given
> 0, suppose that we could not find a suitable
. Then
= 1 would not work and so we must have some x1 such that |x1- p| < 1 and |f(x1) - f(p)| >
.
Similarly,
= 1/2will not work, and so we can find x2 further down the sequence than x1 such that |x2- p| < 1/2 and |f(x2) - f(p)| >
.
Continuing in this way we get a sequence (x1, x2, x3, ... ) which by construction converges to p, but for which f(xn) is always at least
away from f(p). So we cannot have (f(xn)) converging to f(p) and we have a contradiction.

x is continuous.
Proof
Given
> 0 we must show that |
x -
p| <
provided that x, p are close enough.
Now |
x -
p| = |x - p|/|
x +
p| < |x - p| /
p and so choosing
=
/
p will do.

| Previous page (Limits of functions) | Contents | Next page (Some horrible functions) |