> < ^ From:

> < ^ Subject:

Dear Avital and dear gap-forum,

Let G be H x K. Then the self-normalized subgroups of G should be the

subgroups S such that the projections of S onto H and K are

self-normalized in H and K respectively.

Let S be a self-normalized subgroup generated by h_1 x k_1, ...,

h_n x k_n. Then the projection of S onto H is the subgroup S_H of H

generated by h_1, ..., h_n and S_H self-normalized, this can be proved

using (h_i x k_1) ^ (h x k) = (h_i ^ h) x (k_i ^ k) .

The same for the analogous subgroup of K.

Greetings,

Marco

> < [top]