MT2002 Analysis

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The Golden Ratio

The number (1 + sqrt5)/2 = 1.6180339... that we met in the last supplement is what the Ancient Greeks called the Golden Ratio phi. In 1509 the mathematician Luca Pacioli (1445 to 1517) wrote a whole book: Divina proportione (= The divine proportion) about this number.

It occurs in many different places in mathematics.

The number phi satisfies the quadratic equation x2 - x - 1 = 0. A number of interesting identities follow from this. For example, 1/phi = phi - 1 = 0.6180339... and phi2 = phi + 1 = 2.6180339.... Hence phi3 = phi + gamma2 = 1 + 2phi and so phi4= 2phi + 2phi2 = 2 + 3phi and in general phin = an + an+1phi where you might recognise the terms of the sequence (an). (See below.)


Given a rectangle with the property that when you remove a square from it, what is left has the same proportions as the original square, you may verify that this rectangle has the proportions phi : 1.

The Greeks used rectangles of this shape in many of their classical buidings since they believed such a shape was more aesthetically pleasing than any other rectangle.



The Ancient Greeks investigated the geometry of the Pentangle:
They found that the ratio AB : AC is the Golden Ratio phi.

From this a modern mathematician can deduce that 2 cos(36degrees) = gamma.

Since phi can be defined using the square root of a rational, one can construct lines whose lengths have ratio phi using ruler and compass constructions. Hence one may construct an angle of 36degrees by such a method and so construct a regular pentagon by ruler and compass constructions.

You saw on the last page that phi has the continued fraction expansion:

If you take the approximations to phi given by cutting off this continued fraction after 1, 2, 3, ... terms you get the sequence (1 , 2 , 3/2 , 5/3 , 8/5 , 13/8 , ... ) of ratios of the terms of the Fibonacci sequence (which you might have spotted above).

As this last result suggests, phi is closely related to the Fibonacci numbers. For example, the nth Fibonacci number fn = (gamman - phi-n)/sqrt5 and an even cuter formula is fn = [phin/sqrt5] where [x] means the integer part of x.


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JOC September 2002